Number of $C a^{2 +}$ and $C I^{-}$ ions in anhydrous 111 g $C a C l_{2}$ are.

N_{A}^{'}, 2 N_{A}

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2 N_{A}^{'}, N_{A}

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N_{A}^{'}, N_{A}

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None of these

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Solution

The correct option is A $N_{A}^{'}, 2 N_{A}$
111g $C a C I_{2} = 40 g C a^{2 +} = 71 g C I^{-}$
$\equiv N i o n C a^{2 +} \equiv 2 N i o n C l^{-}$

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