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Question

Number of circles that can be drawn through three non-collinear points is

(a) 1

(b) 0

(c) 2

(d) 3

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Solution

(a) 1

Suppose we are given three non-collinear points as A, B and C

1. Join A and B.

2. Join B and C.

3. Draw perpendicular bisector of AB and BC which meet at O as centre of the circle.

So basically we can only draw one circle passing through three non-collinear points A, B and C.

Hence, the correct answer is option (a).


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