1. P things should always be included implies that no. of things left to be selected =n−P
and from n−P things we have to select r things when P things are already selected.
this implies that things left to be selected are r−P
therefore, answer is
= n−PCr−P
2. when P things are always excluded then no. of things left from where we can select r things are n−P things
therefore, answer is
n−PCr
3. similar to our 1st case and 2nd case. P is always included and Q is always excluded implies that out of the n−P−Q things left to be selected, we have to select r−P things since P things are already selected.
therefore, correct answer is
= n−P−QCr−P