Number of complex number z such that |z|=1 and a=z¯z
∣∣∣a+1a∣∣∣ is
A
4
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B
6
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C
0
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D
infinite
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Solution
The correct option is B infinite Let, z=cosx+isinx ⇒∣∣∣z¯z+¯zz∣∣∣=∣∣∣z2+(¯z)2z¯z∣∣∣=1 ⇒|cos2x+isin2x+cos2x−isin2x|=1 =2|cos2x|=1 ⇒cos2x=12orcos2x=−12 ⇒x=nπ±π6,mπ±π3,m,n∈I