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Question

Number of complex number z such that |z|=1 and a=z¯z

a+1a is

A
4
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B
6
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C
0
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D
infinite
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Solution

The correct option is B infinite
Let, z=cosx+isinx
z¯z+¯zz=z2+(¯z)2z¯z=1
|cos2x+isin2x+cos2xisin2x|=1
=2|cos2x|=1
cos2x=12orcos2x=12
x=nπ±π6,mπ±π3,m,nI

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