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Quadrilateral

Number of dia...

Question

Number of diagonals a regular hexagon has____.

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Solution

Dear student,

$N o . o f v e r t i c e s i n a h e x a g o n, n = 6 u \sin g t h e f o r m u l a o f d i a g o n a l s = \frac{n (n - 3)}{2}, w h e r e n i s t h e n u m b e r o f s i d e o f p o l y g o n = \frac{6 \times (6 - 3)}{2} = \frac{6 \times 3}{2} = 9 t h u s, t h e n u m b e r o f d i a g o n a l s a r e g u l a r h e x a g o n h a s i s 9$
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