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Question

Number of dissimilar terms in the expansion of (x1+x2+.....+xn)3 is

A
n2(n+1)24
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B
n(n+1)(n+2)6
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C
n+1C2+nC2
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D
n3+3n24
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Solution

The correct options are
B n(n+1)(n+2)6
C n+1C2+nC2
The number of dissimilar terms in the expression
=3+n1C3
=n+2C3
=(n+2).(n+1).n3!
=n(n+1)(n+2)6.

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