Number of divisors of n=38808 (except 1 and n) is

[RPET 2000]

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Solution

The correct option is A
70

Since, 38808 = $8 \times 4851$

= $8 \times 9 \times 539$ = $8 \times 9 \times 7 \times 7 \times 11$ = $2^{3} \times 3^{2} \times 7^{2} \times 11$

So, numbner of divisors

= (3 + 1)(2 + 1)(2 + 1)(1 + 1) = 72.

This includes two divisors 1 and 38808. Hence, the required number of divisors = 72 -2 = 70

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Similar questions

Number of divisors of n=38808 (except 1 and n) is

[RPET 2000]

Q. Number of divisors of

n = 38808

except

1

and

n

Q. The total number of proper divisors of

38808

excluding

1

and the number itself is

Q. The number of divisors a number

38808

can have, excluding

1

and the number itself is

$= {lim}_{n \to \infty} [\frac{1}{n} + \frac{1}{\sqrt{n^{2} + n}} + \frac{1}{\sqrt{n^{2} + 2 n}} + \dots + \frac{1}{\sqrt{n^{2} + (n - 1) n}}]$ is equal to [RPET 2000]

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Number of divisors of n=38808 (except 1 and n) is [RPET 2000]

The correct option is A 70 Since, 38808 = 8×4851 = 8×9×539 = 8×9×7×7×11 = 23×32×72×11 So, numbner of divisors = (3 + 1)(2 + 1)(2 + 1)(1 + 1) = 72. This includes two divisors 1 and 38808. Hence, the required number of divisors = 72 -2 = 70

Number of divisors of n=38808 (except 1 and n) is

[RPET 2000]