Number of electric lines of force emanating from $1 C$ of positive charge in vacuum is :

8.85 \times 10^{- 12}

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9 \times 10^{9}

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1 / 4 π \times 9 \times 10^{9}

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1.13 \times 10^{11}

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Solution

The correct option is D $1.13 \times 10^{11}$
$ϕ$ from $1 C$ of charge is $= \frac{Q_{e n c l o s e d}}{ϵ_{o}}$
$= \frac{1}{8.8501 \times 10^{- 12}}$

$= 1.129 \times 10^{11}$

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Number of electric lines of force emanating from 1C of positive charge in vacuum is :

The correct option is D 1.13×1011ϕ from 1C of charge is =Qenclosedϵo=18.8501×10−12=1.129×1011

Number of electric lines of force emanating from $1 C$ of positive charge in vacuum is :

The correct option is D $1.13 \times 10^{11}$
$ϕ$ from $1 C$ of charge is $= \frac{Q_{e n c l o s e d}}{ϵ_{o}}$
$= \frac{1}{8.8501 \times 10^{- 12}}$

$= 1.129 \times 10^{11}$