Number of electron that have zero value of magnetic quantum number in $_{15} P$ is:

6

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7

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8

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9

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Solution

The correct option is D $9$
For phosphorus electronic configuration is $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{3}$
Number of electrons with magnetic quantum number 0 is 9
$1 s^{2} = 2$ , $2 s^{2} = 2$ , $2 p^{6} = 2$ , $3 s^{2} = 2$ , $3 p^{3} = 1$
Hence total is $m = 9$

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