Number of electrons having $m_{l} + I$ value equal to zero in an atom of manganese (z = 25) is:

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Solution

The correct option is C 13
$M n \to 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{2} 3 d^{5} F o r s - e^{-}, l = 0, m_{l} = 0 s o m + l = 0 T o t a l n o . o f s - e^{-} \Rightarrow 8 e^{-} F o r p - e^{-}, l = 1, m_{l} = - 1, 0, + 1 F o r d - e^{-}, l = 2, m_{l} = - 2, 0, - 1 + 1, + 2$
One orbital in each p and d subshell would be there which has $m + l = 0$
So total $e^{-} \Rightarrow 8 + 4 + 1 \Rightarrow 13 e^{-}$

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Z = 25

Consider an atom of manganese, represented as $_{25} M n^{55}$ Give the number of :

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