Question

Number of electrons in $1.8$ grams of $H_{2}O$ is:

• A. $6.02\times {10}^{23}$
• B. $3.01\times {10}^{23}$
• C. $0.602\times {10}^{23}$
• D. $60.22\times {10}^{23}$

Answer 1

The correct option is A $6.02\times {10}^{23}$

One molecule of water contains $10$ electrons. One mole of water molecules will contain $10N_A$ electrons. Here, $N_A$ is the Avogadro number.

$1.8$ g of water molecule corresponds to $\frac{1.8}{18}=0.1$ mole. Thus, $0.1$ mole of water molecule contains $0.1\times 10N_A=N_A$ electrons = $6.022\times {10}^{23}$