Number of electrons in an orbit will be:

2 n^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 (2 l + 1)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\sum_{l = 0}^{l = n - 1} 2 (2 l + 1)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

both (1) & (3)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is B both (1) & (3)
Number of electron in an orbit $= 2 n^{2}$
$l = n - 1 \sum p = 0 2 (2 l + 1)$
For $n = 3$
No. of electron $= 2 (3)^{2}$
$= 18$
$l = 2 \sum l = 0 2 (2 l + 1)$
$2 + 10 + 6 = 18$ .

Suggest Corrections

Similar questions

List - I	List - II
A) No of electrons present in an orbit	1) 2
B) Number of orbitals in an orbit	2) $n$
C) Number of electrons in an orbital	3) $n^{2}$
D) Number of sub shells in an orbit	4) $2 n^{2}$
	5) $n + 1$

The correct match is:

Q. 22 ml + 8 ml = _____

Q. The maximum number of electrons that can be accommodated in orbitals with quantum numbers

n = 3, l = 1

and

m = + 1

In 66kg of adulterated milk, the ratio of water to milk was found to be 1 $:$ 5. Water was added to it to make the ratio 3 $:$ 5. The quantity of water added is?

Q. In the formula,

2 n^{2}

for finding the maximum number of electrons in an orbit, what does the 'n' represent?

Join BYJU'S Learning Program

Number of electrons in an orbit will be:

The correct option is B both (1) & (3)Number of electron in an orbit =2n2l=n−1∑p=02(2l+1)For n=3No. of electron =2(3)2=18l=2∑l=02(2l+1)2+10+6=18.

The correct option is B both (1) & (3)
Number of electron in an orbit $= 2 n^{2}$
$l = n - 1 \sum p = 0 2 (2 l + 1)$
For $n = 3$
No. of electron $= 2 (3)^{2}$
$= 18$
$l = 2 \sum l = 0 2 (2 l + 1)$
$2 + 10 + 6 = 18$ .