Question

Number of electrons present in 4f-orbital of $H{o}^{3+}$ ion is __________. (Given: Atomic no. of $Ho=67)$

• A. 10
• B. 10.00
• C. 10.0

Answer 1

Answer: (A), (B), (C)

Electronic configurations of $HoandH{o}^{3+}$ are

$Ho:4f^{11}6s^2$

$H{o}^{3+}:4f^{10}$

$\therefore$ Number of electrons present in $4f$ orbital of $H{o}^{3+}is10$.