Number of ethers that can be formed using the empirical formula $C_{4} H_{10} O$ are:

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Solution

The correct option is B 3
From the empirical formula $C_{4} H_{10} O$ , it is clear that no ring or double bond structure is possible. Now, we can only form 3 isomeric ethers with this formula
$C H_{3} C H_{2} C H_{2} - O - C H_{3}$
$C H_{3} C H_{2} - O - C H_{2} C H_{3}$
$(C H_{3})_{2} C H - O - C H_{3}$
Hence, the correct answer is 3.

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