Number of glucose molecules present in 10ml of decimolar solution

Open in App

Solution

Decimolar means 0.1 M.
Therefore, number of moles of glucose in 10 ml of 0.1 M solution is 0.001, which can be considered as 10^-3
We know that, 1 mole of glucose contains 6.023 x 10^23 molecules,
so 10^-3 moles contains 6.023×10^20 molecules.

Suggest Corrections

Similar questions

Q. The number of glucose molecules present in

10 m l

of decimolar solution is:

100 m l

of an aqueous solution contains

6.0 \times 10^{21}

solute molecules. The solution is diluted to

1

lit. The number of solute molecules present in

10 m l

of the dilute solution is:

Hundred ML of an aqueous solution contains 6.023 $\times 10^{21}$ Solute moleculesThe solution is diluted 1 L The number of solute molecules present in 10ml of dilute solution is

Q. The osmotic pressure of a decimolar solution of glucose at

30^{o} C

is :

Q. The number of milli moles of solute present in 10 ml of decimolar solution is:

Join BYJU'S Learning Program

Number of glucose molecules present in 10ml of decimolar solution

Decimolar means 0.1 M. Therefore, number of moles of glucose in 10 ml of 0.1 M solution is 0.001, which can be considered as 10^-3 We know that, 1 mole of glucose contains 6.023 x 10^23 molecules, so 10^-3 moles contains 6.023×10^20 molecules.

Decimolar means 0.1 M.
Therefore, number of moles of glucose in 10 ml of 0.1 M solution is 0.001, which can be considered as 10^-3
We know that, 1 mole of glucose contains 6.023 x 10^23 molecules,
so 10^-3 moles contains 6.023×10^20 molecules.