Number of gram atoms of oxygen present in $0.3 m o l e$ of $(C O O H)_{2} .2 H_{2} O$ is

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.9

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.8

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
1.8

No. of gram atoms = no. of moles $\times$ $6$ (number of oxygen atoms)

= $0.3 \times 6$ = $1.8$

Suggest Corrections

Similar questions

N_{2} O_{5}

Calculate the number of
(a) Oxygen atoms in 0.10 mole of $N a_{2} C O_{3}$ . $10 H_{2} O$
(b) gram atoms in 4.6 gram of sodium.

1

Number of oxygen atoms present in 1 gram of calcium carbonate are

(C O O H)_{2} .2 H_{2} O

Join BYJU'S Learning Program