Question

Number of H atoms in $34kgN{H}_3$ gas are:

• A. $3.6\times {10}^{27}$
• B. $6\times {10}^{23}$
• C. $18\times {10}^{23}$
• D. $6\times {10}^{27}$

Answer 1

The correct option is A $3.6\times {10}^{27}$

$1molN{H}_3=17g$
$17gcontain3\times 6\times {10}^{23}Hatoms$
Then,
$34gcontain6\times 6\times {10}^{23}Hatom$
Therefore,
$34kgcontain36\times {10}^{23}\times {10}^{3}Hatoms$
Number of H atoms in 34 kg of $N{H}_3=3.6\times {10}^{27}$