Question

Number of hydroxyl group in compound ‘Y’ is:

Answer 1

Step 1: Formation of double bond

The catalyst used here is ${\mathrm{H}}_2/\mathrm{Pd},{\mathrm{BaSO}}_4$, which reduces the triple bond present in the middle of the compound into a double bond.

Thus the compound X formed is:

Step 2: Oxidation to form hydroxyl group

Now after the formation of the compound X, $\mathrm{dil}.{\mathrm{KMnO}}_4$is used at a temperature of $273\mathrm{K}$.

The oxidising effect of the $\mathrm{dil}.{\mathrm{KMnO}}_4$produces hydroxyl group$(-\mathrm{OH})$ in all the carbons that have a double bond.

The resulting compound Y so formed is:

From the compound Y, we can see that there are a total of 6 hydroxyl groups$(-\mathrm{OH})$ present.

Therefore, number of hydroxyl group$(-\mathrm{OH})$ in compound ‘Y’ is 6.