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Question

Number of identical terms in the sequence 2,5,8,11.... upto 100 terms are

A
17
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B
33
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C
50
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D
147
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Solution

The correct option is A 33
First sequence is 2,5,8,11,..... upto 100 terms
Here, nth term is 2+(n1)3
Alternate terms are 5,11,17,.....
term of common sequence,
tn=5+(n1)6=(6n1)
Also, 100th term of the first sequence
=2+(1001)3=201
tn201
6n1201
6n202
n3323
n=33
(nN)

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