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Byju's Answer
Standard XII
Mathematics
Differentiation under Integral Sign
Number of int...
Question
Number of integer(s) for which the function
f
(
x
)
=
sin
−
1
(
log
2
(
x
3
)
)
is defined is
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Solution
y
=
sin
−
1
(
log
2
(
x
3
)
)
y
=
sin
−
1
θ
is defined for
θ
∈
[
−
1
,
1
]
⇒
−
1
≤
log
2
(
x
3
)
≤
1
⇒
1
2
≤
x
3
≤
2
⇒
3
2
≤
x
≤
6
Integers are
2
,
3
,
4
,
5
,
6
⇒
5
integers
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Differentiation under Integral Sign
Standard XII Mathematics
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