Question

Number of integers lying between $1$ to $102$ which are divisible by all $\sqrt{2},\sqrt{3},\sqrt{6},$ is:

• A. $16$
• B. $17$
• C. $15$
• D. $0$

Answer 1

The correct option is D $0$

For a number to be divisible by $\sqrt{2}$, it must be an irrational number.

Since an integer is not an irrational, there are no integer numbers between $1$ to $102$ which are divisible by all $\sqrt{2},\sqrt{3},\sqrt{6}$.

Therefore, option $D$ is correct.