Question

Number of intersecting points of the conic $4x^2+9y^2=1$ and $4x^2+y^2=4$ is

• A. $1$
• B. $2$
• C. $3$
• D. $0$ (zero)

Answer 1

The correct option is D $0$ (zero)

$C_1:\frac{x^2}{1/4}+\frac{y^2}{1/9}=1C_2:\frac{x^2}{1}+\frac{y^2}{4}=1$


From their graphs, we can conclude that $C_1$ lies inside $C_2$ such that there is no intersecting point.