Question

Number of ion pairs in CsCl unit cell is:

• A. 1
• B. 2
• C. 4
• D. 8

Answer 1

Answer: (A)

1

$C{s}^{+}$ is present at the cubic hole and the $C{l}^{-}$ is present at the corners of the cube, forms a simple cubic lattice.

No. of $C{s}^{+}$ ion per unit cell is 1 and the no. of $C{l}^{-}$ ion $=8\times \frac{1}{8}=1$ per unit cell.

Option A is the correct answer.