Number of isomeric compounds that are possible with the formula $C_{4} H_{10} O$ are:

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Solution

The correct option is D 7
Since the compound contains one oxygen atom, hence alcohol and ether are possible. Also compound do not contain ring or double bond because the degree of unsaturation is zero.

$(i) C H_{3} C H_{2} C H_{2} C H_{2} - O H$
$B u t a n - 1 - o l$

$(i i) C H_{3} C H (O H) C H_{2} C H_{3}$
$2 - B u t a n o l$

$(i i i) (C H_{3})_{2} C H_{2} C H_{2} - O H$
$2 - m e t h y l p r o p a n - 1 - o l$

$(i v) (C H_{3})_{3} C - O H$
$2 - m e t h y l p r o p a n e - 2 - o l$

$(v) C H_{3} C H_{2} C H_{2} - O C H_{3}$
$1 - m e t h o x y p r o p a n e$

$(v i) C H_{3} C H_{2} O C H_{2} C H_{3}$
$e t h o x y$ $e t h a n e$

$(v i i) (C H_{3})_{2} C H O C H_{3}$
$2 - m e t h o x y$ $p r o p a n e$

Only seven isomers are possible.

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