Number of lone pairs around phosphorus in $P C l_{5}, P C l_{4}^{+}$ and ${P C l_{6}}^{-}$ are respectively

0, 1, 2

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0, 0, 0

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1, 2, 3

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0, 2, 1

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Solution

The correct option is B $0, 0, 0$
$P$ atom has $5$ valence electrons, $P C l_{5}$ , all $5$ electrons involed in bonding.

$P C l_{4}^{+}$ : $+$ sign signifies loss of $1$ electron, rest $4$ involved in bonding.

$P C l_{6}^{-}$ : $-$ sign signifies gain of $1$ electron, all $6$ involved in bonding.

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Similar questions

∠ C l P C l

P C l_{5}, P C l_{4}^{+}, P {C l}_{6}^{-}

P C l_{5} (s)

P C l_{4}^{+}

P C l_{6}^{-}

P C l_{5}

[P C l_{4}]^{+} [P C l_{6}]^{-}

In solid state $P C l_{5}$ exists as

P C l_{5}

P C l_{4}^{+}

P C l_{6}^{-}

2 P C l_{5} ⇌ P C l_{4}^{+} + P C l_{6}^{-}

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