Question

Number of methyl substitutions takes place in the ring when aniline is reacted with $C{H}_{3}Cl$ in the presence of $AlC{l}_3$?

• A. $0$
• B. $1$
• C. $2$
• D. $3$

Answer 1

The correct option is A $0$

Aniline does not undergo Friedel craft's reaction and no methyl group is substituted. Howevere $-N{H}_2$ group gets coordinated with the lewis acid and salt is formed between lewis acid and aniline.
$+R$ effect of $–N{H}_2$ diminished due to ​salt formation.