Number of molecules in $14 g$ of carbon monoxide is

12.044 \times 10^{23}

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6.022 \times 10^{23}

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3.011 \times 10^{23}

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1.5050 \times 10^{23}

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Solution

The correct option is C $3.011 \times 10^{23}$
The molar mass of CO is $12 g / m o l + 16 g / m o l = 28 g / m o l$ .
14 g of CO corresponds to $\frac{14 g}{28 g / m o l} = 0.5 m o l$ .
The number of molecules present in 0.5 mol of CO is $0.5 m o l \times 6.023 \times 10^{23} m o l e c u l e s / m o l = 3.011 \times 10^{23}$
Thus, the number of molecules in 14g of carbon monoxide is $3.011 \times 10^{23}$ .

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6.022 \times 10^{23}

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6.022 \times 10^{23}

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Number of molecules in 14g of carbon monoxide is

The correct option is C 3.011×1023The molar mass of CO is 12g/mol+16g/mol=28g/mol.14 g of CO corresponds to 14g28g/mol=0.5mol.The number of molecules present in 0.5 mol of CO is 0.5mol×6.023×1023molecules/mol=3.011×1023Thus, the number of molecules in 14g of carbon monoxide is 3.011×1023.

Number of molecules in $14 g$ of carbon monoxide is