Number of molecules present in $14$ gm of $N_{2}$ molecule is:

6.022 \times 10^{23}

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3.011 \times 10^{23}

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1.51 \times 10^{23}

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6.022 \times 10^{22}

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Solution

The correct option is B $3.011 \times 10^{23}$
$N_{2} = \frac{14}{28} = 0.5$
Number of Nitrogen molecules $= 0.5 \times 6.023 \times 10^{23}$
So answer is $3.01 \times 10^{23}$ .

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Number of molecules present in 14gm of N2 molecule is:

The correct option is B 3.011×1023N2=1428=0.5Number of Nitrogen molecules=0.5×6.023×1023So answer is 3.01×1023.

Number of molecules present in $14$ gm of $N_{2}$ molecule is:

The correct option is B $3.011 \times 10^{23}$
$N_{2} = \frac{14}{28} = 0.5$
Number of Nitrogen molecules $= 0.5 \times 6.023 \times 10^{23}$
So answer is $3.01 \times 10^{23}$ .