Number of moles of K2Cr2O7 require to reduce one mole of Sn2+ ions is
A
1/3
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B
3
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C
1/6
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D
6
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Solution
The correct option is A 1/3 one mole of Sn2+ require 2 mole of electron to reduce and one mole of K2Cr2O7 give 6 mole of electron so one mole of Sn2+ require (1/3) mole of K2Cr2O7 for reduction.