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Byju's Answer
Standard XII
Chemistry
Potassium Dichromate
Number of mol...
Question
Number of moles of
K
2
C
r
2
O
7
reduced by one mole of
S
n
2
+
ions (in acidic medium) is:
A
1
3
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B
3
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C
6
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D
1
6
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Solution
The correct option is
A
1
3
Reaction that occurs between
C
r
2
O
2
−
7
and
S
n
2
+
ion is:
C
r
2
O
2
−
7
+
S
n
2
+
H
+
−
−
→
C
r
3
+
+
S
n
4
+
+
H
2
O
Reduction half:
+
6
C
r
2
O
2
−
7
→
2
C
r
3
+
;
n-factor
=
3
×
2
=
6
Oxidation half:
S
n
2
+
→
S
n
4
+
;
n-factor
=
2
Since 6 mol of
S
n
2
+
are used by 2 mol of
C
r
2
O
2
−
7
. Hence 1 mol of
S
n
2
+
will be used by
1
3
mol of
C
r
2
O
2
−
7
.
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