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Question

Number of moles of K2Cr2O7 reduced by one mole of Sn2+ ions (in acidic medium) is:

A
13
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B
3
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C
6
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D
16
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Solution

The correct option is A 13
Reaction that occurs between Cr2O27 and Sn2+ ion is:
Cr2O27+Sn2+H+Cr3++Sn4++H2O

Reduction half: +6Cr2O272Cr3+; n-factor=3×2=6
Oxidation half: Sn2+Sn4+; n-factor=2

Since 6 mol of Sn2+ are used by 2 mol of Cr2O27. Hence 1 mol of Sn2+ will be used by 13 mol of Cr2O27.

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