Number of moles of $K M n O_{4}$ in acid medium required to oxidize $10$ moles of $F e C_{2} O_{4}$ is :

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Solution

The balanced reaction is as follows:
$10 F e C_{2} O_{4} + 6 K M n O_{4} + 24 H_{2} S O_{4} \to 3 K_{2} S O_{4} + 6 M n S O_{4} + 5 F e_{2} (S O_{4})_{3} + 24 H_{2} O + 20 C O_{2}$
So, according to the above reaction, number of moles of $K M n O_{4}$ in acid medium required to oxidize 10 moles of $F e C_{2} O_{4}$ is 6.

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