Question

number of moles of KMnO₄ that is needed to react with one mole of FeC₂O₄ in acidic medium is-

a) 2/5 b)3/5 c)4/5 d)(y-x)

Answer 1

A) 3/5......

KMnO4 + FeC2O4 + H ------> Mn2+ + Fe3+ + 2CO2

KMnO4 = 5 electrons

ferrous oxalate in acidic solution = 3 electrons

while reaction exchange of electrons takes place..........so

3 moles of KMnO4 = 5 moles of FeC2O4

5 moles of FeC2O4 = 3 moles of KMnO4

so 1 mole of FeC2O4 = 3/5 moles of KMnO4

hence 3/5 moles of KMnO4 of KMnO4 will be needed to react completely with one mole of ferrous oxalate in acidic solution.....