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Question

Number of moles of MnO4 required to oxidize 1 mole of ferrous oxalate completely in acidic medium will be?

A
0.4
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B
0.6
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C
0.2
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D
7.5
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Solution

The correct option is B 0.6
Let us take the reaction between ferrous oxalate and MnO4 in presence of sulphuric acid as:

FeC2O4+KMnO4+H2SO4K2SO4+MnSO4+Fe2(SO4)3+H2O+CO2

While, the balanced form of reaction is:

10FeC2O4+6KMnO4+24H2SO43K2SO4+6MnSO4+5Fe2(SO4)3+24H2O+20CO2

So, we see that, 6 moles of KMnO4 is required to oxidize 10 moles of FeC2O4.

So, 1 mole of FeC2O4 would be oxidized by = 6/10 = 0.6 moles of KMnO4.
So, the answer is (a).

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