Question

Number of moles of $Mn{O}_4{}^{-}$ required to oxidize one mole of ferrous oxalate completely in acidic medium will be:

• A. $7.5$ moles
• B. $0.2$ moles
• C. $0.6$ moles
• D. $0.4$ moles

Answer 1

Answer: (C)

$0.6$ moles

No. of moles of ${MnO}_4^{-}$ required to oxidize one mole of ${FeC}_2{O}_4$ completely in acidic medium.

$3{MnO}_4^{-}+{24H}^{+}+5{FeC}_2{O}_4⟶{3Mn}^{+2}+{12H}_{2}O+{10CO}_2+{5Fe}^{+3}$

$5$ moles of ${FeC}_2{O}_4$ reacts with $3$ moles of ${MnO}_4^{-}$.

$5molesof{FeC}_2{O}_4⟶3molesof{MnO}_4^{-}1moleof{FeC}_2{O}_4⟶\frac{3}{5}molesof{MnO}_4^{-}$

$\therefore$ The number of moles of $Mn{O}_4^{-}$ required to oxidize one mole of ferrous oxalate completely in the acidic medium will be 0.6 moles.

Hence, option $C$ is correct.