Question

Number of moles of nitrogen in 1 L of air containing 78%nitrogen by volume at STP will be

Answer 1

Dear Student,
Given " volume % = 78% N₂
Volumne of air = 1L
Volume % = $\frac{volumeof{N}_2}{Volumeofair}\times 100$
putting the values we get
$78=\frac{V_{N2}}{1}\times 100$
V_N2 = 0.78
At STP 22.4 L =1mole
so 0.78 L = $\frac{1}{22.4}\times 0.78$= 0.34 moles
Regards!