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Stoichiometry

Number of mol...

Question

Number of moles of oxygen produced during the decomposition of 1 mole of lead nitrate is:

A

0.5

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B

1

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C

1.5

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D

2

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Solution

The correct option is A $0.5$
The decomposition reaction can be written as:

$2 P b (N O_{3})_{2} \to 2 P b O + 4 N O_{2} + O_{2}$

$∴$ 2moles of $P b (N O_{3})_{2}$ produce = 1 mole of $O_{2}$

1 mole of $P b (N O_{3})_{2}$ produces = 0.5 moles of $O_{2}$

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