Number of moles of oxygen required for the combustion of hexyne and toluene respectively are :

8

and

9

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\frac{17}{2}

and

8

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\frac{17}{2}

and

9

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9

and

\frac{17}{2}

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Solution

The correct option is C $\frac{17}{2}$ and $9$
When hexyne $(C_{6} H_{10})$ burns, it produce $6$ moles of $C O_{2}$ and $5$ moles of $H_{2} O$

$C_{6} H_{10} + (\frac{17}{2}) O_{2} ⟶ 6 C O_{2} + 5 H_{2} O$

$\frac{17}{2}$ moles of $O_{2}$ is required for the combustion of hexyne

When toluene $(C_{7} H_{8})$ burns, it produce $7$ moles of $C O_{2}$ and $4$ moles of $H_{2} O$

$C_{7} H_{8} + 9 O_{2} \to 7 C o_{2} + 4 H_{2} O$

$9$ moles of $O_{2}$ is required for the combustion of toluene.

Hence the correct option is C.

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Similar questions

\to

\in

Find the leftmost and the rightmost number when the following are represented on the number line.

$\frac{- 19}{10}, \frac{- 9}{5}, \frac{- 8}{5}, \frac{- 3}{2}, \frac{- 17}{10}$

X	$5 - 9$	$9 - 13$	$13 - 17$	$17 - 21$
F	$3$	$8$	$9$	$4$

3 (5 z - 7) - 2 (9 z - 11) = 4 (8 z - 13) - 17

(- 8) + (- 9) + (+ 17)

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