Question

Number of moles of oxygen required for the combustion of one mole of an alkane is equal to:

• A. n+1
• B. $\frac{n+1}{2}$
• C. $\frac{3n+1}{2}$
• D. n

Answer 1

Answer: (C)

$\frac{3n+1}{2}$

The equation for complete combustion of alkane can be written as:
$C_n{H}_{2n+2}+\left(\frac{3n+1}{2}\right)O_2\to nC{O}_2+(n+1)H_{2}O$ ; where n= no. of carbon atoms.