Number of moles of $S n C l_{2}$ required for the reduction of $K_{2} C r_{2} O_{7}$ into $C r_{2} O_{3}$ is (in acidic medium) :

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Solution

The correct option is A 3
$K_{2} C r_{2} O_{7} + 3 S n C l_{2} + 14 H C l \to 2 C r C l_{3} + 3 S n C l_{4} + 2 K C l + 7 H_{2} O$

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