Question

Number of moles of water in $488.6$ g of $BaC{l}_2.2H_{2}O$ is:

[Molecular weight of $BaC{l}_2.2H_{2}O$ $=$ $244.33$]

• A. 2 moles
• B. 4 moles
• C. 3 moles
• D. 5 moles

Answer 1

The correct option is B 4 moles

$488.6$ g of barium chloride dihydrate corresponds to $\frac{488.6}{244.3}=2$ moles.

$1$ mole of barium chloride dihydrate contains $2$ moles of water.

So, $2$ moles of barium dichloride will contain $4$ moles of water.

Hence, option B is correct.