Number of moles present in $128 g m$ of sulphur $(S_{8})$ is

4

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1

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8

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0.5

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Solution

The correct option is C $0.5$
$M o l e c u l a r w e i g h t o f S = 32 g m M o l e c u l a r w e i g h t o f S_{8} = 256 g m n o . o f m o l e s = \frac{G i v e n m a s s}{M o l a r m a s s} = \frac{128}{256} = 0.5 m o l e s$

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