Question

Number of natural numbers between $100$ & $1000$ such that at least one of their digits is $6$ is m, then which of the following digit occurs in m.

• A. $1$
• B. $2$
• C. $5$
• D. $6$

Answer 1

Answer: (A), (B), (C)

The correct options are
A $1$
B $2$
C $5$

The number of such numbers is equal to

Total numbers between 100 and 1000- (numbers where the digit '6' is absent)

$=(900-1)-\left(648\right)$

$=251$

Hence the the required number of numbers are $251$.