wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The number of natural numbers less than 1000, in which no two digits are repeated, is equal to:


A

738

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

792

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

837

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

720

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

738


Explanation for the correct option:

Finding the number of natural numbers less than 1000, in which no two digits are repeated, is equal to:

Number of 1 digit Natural numbers that is less than 1000=9

Number of two digit number in which no two digits are repeated=9×9=81

(For one's place we have 9 choice for ten's place we have 9 choices (one number placed already) )

Number of three digit number in which No. two digit are repeated =9x9x8=648

(For hundred place we have 9choice (0 excluded) for ten's place we have 9 choices & for one's place we have 8 choices )

Hence, total number less than 1000 when two-digit numbers are not repeated =9+81+648=738

Hence the correct answer is option (A).


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Permutation
QUANTITATIVE APTITUDE
Watch in App
Join BYJU'S Learning Program
CrossIcon