Question

Number of neutrons present in $36g$ of $H_{2}O$

• A. $16$ $N$
• B. $18$ $N$
• C. $36$ $N$
• D. $10$ $N$

Answer 1

The correct option is A $16$ $N$

Moles of this amount is $n=\frac{36gm}{18gm/mole}=2$

So number of molecules will be $2N$, $N$ is Avogadro number

As one molecule contains $16-8=8$ nuetrons $\text{(hydrogen don't possess nuetrons)}$

so total nuetrons $8\times 2N=16N$