Question

Number of Nokia cellular phones sold by store R is what percent more than the total number of Samsung cellular phones sold by stores P and Q together?

• A. $23\frac{1}{17}\%$
• B. $19\frac{5}{17}\%$
• C. $20\frac{3}{17}\%$
• D. $17\frac{11}{17}\%$
• E. $4\frac{24}{119}\%$

Answer 1

The correct option is E $4\frac{24}{119}\%$


Total Number of phones= 11200
$\begin{array}{cc}Store& Nokia/Samsung\\ P& 4:3\\ Q& 3:1\\ R& 5:4\\ S& 7:6\\ T& 1:4\\ U& 11:10\end{array}$
Samsung phones sold by store
$P=\frac{3}{7}\times \frac{14}{100}\times 11200=672$
Samsung phones sold by store
$Q=\frac{1}{4}\times 100=\frac{10}{100}\times 11200=280$
Total Samsung phones sold by (P + Q) = 672 + 280 = 952
Total Nokia phone sold by R = 996
Difference = 996 - 952 = 44
Required percentage, $=\frac{44}{952}\times 100=\frac{44\times 25}{238}=\frac{22\times 25}{119}$
$=\frac{550}{119}=4\frac{24}{119}$%