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Byju's Answer
Standard XII
Mathematics
Fundamental Principle of Counting
Number of num...
Question
Number of numbers divisible by
25
that can be formed without repetition using only the digits
1
,
2
,
3
,
4
,
5
,
0
taken five at a time is
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Solution
1
,
2
,
3
,
4
,
5
,
0
A number divisible by
25
if the last two digits are
25
or
50.
Case
1
:
If the last two digits are
25
So, number of possible numbers
=
3
×
3
×
2
=
18
(as first digit can not be zero)
Case
2
:
If the last two digits are
50
So, number of possible numbers
=
4
×
3
×
2
=
24
Therefore, total possible numbers
=
18
+
24
=
42
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