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Question

Number of numbers divisible by 25 that can be formed without repetition using only the digits 1,2,3,4,5,0 taken five at a time is

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Solution

1,2,3,4,5,0
A number divisible by 25 if the last two digits are 25 or 50.
Case 1: If the last two digits are 25


So, number of possible numbers =3×3×2=18
(as first digit can not be zero)

Case 2: If the last two digits are 50


So, number of possible numbers =4×3×2=24
Therefore, total possible numbers =18+24=42

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