Number of odd numbers of five distinct digits can be formed by the digits $0, 1, 2, 3, 4,$ is

24

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120

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48

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36

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Solution

The correct option is D $36$

We have total digits $0, 1, 2, 3, 4.$
We want to form odd number, then at last digit can become $1$ or $3$ .
So, two number are fixed for last.
Now, we have option for $1 s t, 2 n d, 3 r d$ and $4 t h$ place are $3, 3, 2, 1$

So , number of getting odd numbers using given five distinct digit $= 3 \times 3 \times 2 \times 1 \times 2 = 36$

Hence, this is the answer.

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Number of odd numbers of five distinct digits can be formed by the digits 0,1,2,3,4, is

Number of odd numbers of five distinct digits can be formed by the digits $0, 1, 2, 3, 4,$ is