Number of permutations of the letters of the word $^{'} M E S M E R I S E^{'}$ is

\frac{9!}{2!^{2} \times 3!}

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9!

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\frac{9!}{7!}

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none of these

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Solution

The correct option is A $\frac{9!}{2!^{2} \times 3!}$
In MESMERISE
Number of M =2
Number of E=2
Number of S=2
NUMBER of R=1
Number of I =1
Number of permutations $= \frac{9!}{2!^{2} 3!}$

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