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Byju's Answer
Standard XII
Physics
Intensity vs Photocurrent
Number of pho...
Question
Number of photons emitted by a 50 W lamp in 5 hour
λ
p
h
o
t
o
n
=
589
A
0
_____________.
A
2.7
×
10
24
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B
2.7
×
10
25
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C
2.7
×
10
26
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D
2.7
×
10
27
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Solution
The correct option is
A
2.7
×
10
24
Since,
1
W
=
1
J
/
s
Therefor,
50
W
=
50
J
/
s
We know that, Energy
=
h
c
λ
=
1242
5893
×
1.6
×
10
−
19
×
10
∴
E
=
3.372
×
10
−
19
J
∵
Power
=
E
t
.50
=
(
3.372
5
×
3600
)
m
=
2.66
×
10
24
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0
Similar questions
Q.
Calculate the number of photons emitted in 10 hour by a 60 W sodium lamp.[
λ
p
h
o
t
o
n
= 5893
λ
]
Q.
A gas of identical hydrogenic atoms has some atoms in ground state and same atoms in certain excited states and there are no atom in any other energy level. The atoms of the gas makes transition to higher energy level by absorbing a light of photon energy of
2.7
e
V
.
Subsequently, the atoms emit radiations of only
6
different photon energy some of them have emitted photons of energy
2.7
e
V
, some have energy more and some have less than
2.7
e
V
. Find :
(i) Principle Quantum no. of atoms in excited state
(ii) Find ionisation energy of gaseous atom.
(iii) Find maximum and minimum energies of emitted photons.
Q.
2.7
÷
100
Q.
A gas of identical hydrogen-like atoms has some atoms in the lowest (ground) energy level A and some atoms in a particular upper (excited) energy level B and there are no atoms in any other energy level. The atoms of the gas make transition to a higher energy level by absorbing monochromatic light of photon energy 2.7 e V. Subsequently , the atom emits radiation of only six different photon energies. Some of the emitted photons have energy of 2.7 eV, some have energy more , and some have less than 2.7 e V.
(a) Find the principal quantum number of the intially excited level B
(b) Find the ionization energy for the gas atoms.
(c) Find the maximum and the minimum energies of the emitted photons.
Q.
Compare the following numbers:
2.7
×
10
12
;
1.5
×
10
8
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