Number of plants
0-2
2-4
4-6
6-8
8-10
10-12
12-14
Number of house
1
2
1
5
6
2
3
mean is 8.4.Is it true or false?

True

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False

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Ambiguous

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Data insuffcient

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Solution

The correct option is B False
$F o r g r o u p e d d a t a w h e n C l a s s I n t e r v a l i s g i v e n, w e f i n d t h e C l a s s M a r k . C l a s s M a r k = m i d p o i n t o f a n i n t e r v a l = \frac{(L o w e r l i m i t + U p p e r l i m i t)}{2} C l a s s M a r k i s t a k e n a s x_{i} f o r e a c h c l a s s i n t e r v a l . F i n d x_{i} f_{i} . F r o m t h e t a b l e, w e h a v e Σ x_{i} f_{i} = 162 & Σ f_{i} = 20 M e a n = \frac{Σ x_{i} f_{i}}{Σ f_{i}} = \frac{162}{20} = 8.1$

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Similar questions

20

Number of Plants	0-2	2-4	4-6	6-8	8-10	10-12	12-14
Number of houses	1	2	1	5	6	2	3

Find median

Class interval 0-2. 2-4 4-6 6-8 8-10 10-12 12-14

Plants. 1. 2. 1. 5. 6. 2. 3

Number of Plants	0-2	2-4	4-6	6-8	8-10	10-12	12-14
Number of houses	1	2	1	5	6	2	3

score	2-4	4-6	6-8	8-10	10-12	12-14
students	12	10	15	14	16	22

1^{2} \times 2^{2} \times 3^{3} \times 4^{4} \times 5^{5} \times 6^{6} \times 7^{7} \times 8^{8} \times 9^{9} \times 10^{10}

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